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The thermal decomposition of orthotelluric acid

H6TeO6 → H2TeO4 + 2H2O


The thermal decomposition of orthotelluric acid to produce metatelluric acid and water. This reaction takes place at a temperature near 140°C and an overpressure.


Picture of reaction: img1 BB html

Сoding to search: H6TeO6 cnd [ temp ] = H2TeO4 + 2 H2O

Add / Edited: 13.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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