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The thermal decomposition of orthotelluric acid

2H6TeO6 → 2TeO2 + O2 + 3H2O

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The thermal decomposition of orthotelluric acid to produce tellurium(IV) oxide, oxygen and water. This reaction takes place at a temperature of 400-600°C.

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Сoding to search: 2 H6TeO6 cnd [ temp ] = 2 TeO2 + O2 + 3 H2O

Add / Edited: 13.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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