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Vanadium(IV) chloride react with disulfur dichloride and chlorine

2VCl4 + S2Cl2 + 3Cl2 → 2(SCl3)[VCl5]


Vanadium(IV) chloride react with disulfur dichloride and chlorine to produce trichloridosulfur(IV) pentachloridovanadate(IV). This reaction takes place at a temperature of 20-30°C.


Picture of reaction: img1 BB html

Сoding to search: 2 VCl4 + S2Cl2 + 3 Cl2 = 2 SCl3VCl5

Add / Edited: 16.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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