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The thermal decomposition of vanadium(V) oxide

2V2O5 → 4VO2 + O2

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The thermal decomposition of vanadium(V) oxide to produce vanadium(IV) oxide and oxygen. This reaction takes place at a temperature of 700-1250°C. Impurities: V6O13.

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Сoding to search: 2 V2O5 cnd [ temp ] = 4 VO2 + O2

Add / Edited: 16.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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