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The thermal decomposition of vanadium(V) sulfide

V2S5 → 2VS + 3S

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The thermal decomposition of vanadium(V) sulfide to produce vanadium(II) sulfide and sulfur. This reaction takes place at a temperature near 950°C.

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Сoding to search: V2S5 cnd [ temp ] = 2 VS + 3 S

Add / Edited: 17.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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