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Vanadium(III) sulfate react with sulfuric acid and water

V2(SO4)3 + H2SO4 + 8H2O → 2{H[V(SO4)2]•4H2O}


Vanadium(III) sulfate react with sulfuric acid and water to produce tetrahydrate hydrogen disulfatovanadate(III). Sulfuric acid - concentrated solution. This reaction slowly takes place in the ethanol, at a temperature near 0°C.
 


Picture of reaction: img1 BB html

Сoding to search: V2SO43 + H2SO4 + 8 H2O = 2 HVSO42 • 4H2O

Add / Edited: 17.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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