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Phosphorus iodide-difluoride react with mercury

2PF2I + 2Hg → P2F2 + Hg2I2


Phosphorus iodide-difluoride react with mercury to produce diphosphorus difluoride and mercury(I) iodide. The reaction proceeds at room temperature. The yield was 86%.[16]


Picture of reaction: img1 BB html

Сoding to search: 2 PF2I + 2 Hg = P2F2 + Hg2I2

Add / Edited: 24.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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