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Silver(I) chloride react with ammonia

AgCl + 2NH3 ⇄ [Ag(NH3)2]Cl

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Silver(I) chloride react with ammonia to produce diamminesilver(I) chloride. This reaction takes place at a temperature of -40°C.

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Сoding to search: AgCl + 2 NH3 = AgNH32Cl

Add / Edited: 26.10.2014 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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