KI + H2SO4 = K2SO4 + I2 + H2S + H2O | Potassium iodide react with sulfuric acid

8KI + 5H₂SO₄ 4K₂SO₄ + 4I₂ + H₂S + 4H₂O

Potassium iodide react with sulfuric acid to produce potassium sulfate, iodine, hydrogen sulfide and water. Potassium iodide - solid. Sulfuric acid - concentrated solution. The reaction takes place in a boiling solution.

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Potassium iodide react with sulfuric acid

8KI + 5H₂SO₄ 4K₂SO₄ + 4I₂ + H₂S + 4H₂O

Picture of reaction:

Сoding to search: 8 KI + 5 H2SO4 cnd [ temp ] = 4 K2SO4 + 4 I2 + H2S + 4 H2O

Add / Edited: 11.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Potassium iodide react with sulfuric acid

8KI + 5H2SO4 4K2SO4 + 4I2 + H2S + 4H2O

Picture of reaction:

Сoding to search: 8 KI + 5 H2SO4 cnd [ temp ] = 4 K2SO4 + 4 I2 + H2S + 4 H2O

Add / Edited: 11.01.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

8KI + 5H₂SO₄ 4K₂SO₄ + 4I₂ + H₂S + 4H₂O

Add / Edited: 11.01.2015 /