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Silver(I) iodide react with ammonia

AgI + 4NH3 → [Ag(NH3)4]I




Silver(I) iodide react with ammonia to produce tetraamminesilver(I) iodide. This reaction takes place at a temperature near -40°C.


Picture of reaction: img1 BB html

Сoding to search: AgI + 4 NH3 = AgNH34I

Add / Edited: 16.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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