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Sodium tetrahydroxoaluminate react with boron chloride

3Na[AlH4] + BCl3 → 3NaCl + 3AlCl3 + 2B2H6

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Sodium tetrahydroxoaluminate react with boron chloride to produce sodium chloride, aluminum chloride and diborane.

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Сoding to search: 3 NaAlH4 + BCl3 = 3 NaCl + 3 AlCl3 + 2 B2H6

Add / Edited: 19.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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