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Sodium tetrahydroxoaluminate react with formic acid

Na[AlH4] + 6HCOOH → 2CH3OH + HCOONa + Al(HCOO)3 + 2H2O




Sodium tetrahydroxoaluminate react with formic acid to produce metanola, sodium formate, aluminum formate and water.


Picture of reaction: img1 BB html

Сoding to search: NaAlH4 + 6 HCOOH = 2 CH3OH + HCOONa + AlHCOO3 + 2 H2O

Add / Edited: 19.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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