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Aluminum iodide react with sodium hydroxide

AlI3 + 4NaOH → Na[Al(OH)4] + 3NaI




Aluminum iodide react with sodium hydroxide to produce sodium tetrahydroxoaluminate and sodium iodide.


Picture of reaction: img1 BB html

Сoding to search: AlI3 + 4 NaOH = NaAlOH4 + 3 NaI

Add / Edited: 19.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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