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Gold(III) chloride react with hydrogen sulfide

2AuCl3 + 3H2S → Au2S3 + 6HCl




Gold(III) chloride react with hydrogen sulfide to produce gold(III) sulfide and hydrogen chloride. This reaction takes place in the medium of ester.


Picture of reaction: img1 BB html

Сoding to search: 2 AuCl3 + 3 H2S = Au2S3 + 6 HCl

Add / Edited: 24.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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