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Gold(III) chloride react with potassium iodide

AuCl3 + 4KI → AuI + K[I(I)2] + 3KCl




Gold(III) chloride react with potassium iodide to produce gold iodide potassium diiodoiodate(I) and potassium chloride.


Picture of reaction: img1 BB html

Сoding to search: AuCl3 + 4 KI = AuI + KII2 { KI3 } + 3 KCl

Add / Edited: 24.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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