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Gold(III) chloride react with iron(II) sulfate

AuCl3 + 3FeSO4 → Au + Fe2(SO4)3 + FeCl3




Gold(III) chloride react with iron(II) sulfate to produce gold, iron(III) sulfate and iron(III) chloride. This reaction takes place at a temperature near 200°C.


Picture of reaction: img1 BB html

Сoding to search: AuCl3 + 3 FeSO4 cnd [ temp ] = Au + Fe2SO43 + FeCl3

Add / Edited: 24.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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