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Hydrogen tetrachloridoaurate(III) react with hydrogen sulfide

2H[AuCl4] + 3H2S → 2Au + 3S + 8HCl




Hydrogen tetrachloridoaurate(III) react with hydrogen sulfide to produce gold, sulfur and hydrogen chloride. The reaction takes place in a boiling solution.


Picture of reaction: img1 BB html

Сoding to search: 2 HAuCl4 + 3 H2S = 2 Au + 3 S + 8 HCl

Add / Edited: 24.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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