H[AuCl4] + KOH + HCHO = Au + HCOOK + KCl + H2O |

2H[AuCl₄] + 11KOH + 3HCHO → 2Au + 3HCOOK + 8KCl + 8H₂O

Hydrogen dichloridoaurate(III) react with potassium hydroxide and formaldehyde to produce gold, potassium formate, potassium chloride and water.

As a result, reaction is produced colloid gold.

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Hydrogen dichloridoaurate(III) react with potassium hydroxide and formaldehyde

2H[AuCl₄] + 11KOH + 3HCHO → 2Au + 3HCOOK + 8KCl + 8H₂O

Picture of reaction:

Сoding to search: 2 HAuCl4 + 11 KOH + 3 HCHO = 2 Au + 3 HCOOK + 8 KCl + 8 H2O

Add / Edited: 24.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Hydrogen dichloridoaurate(III) react with potassium hydroxide and formaldehyde

2H[AuCl4] + 11KOH + 3HCHO → 2Au + 3HCOOK + 8KCl + 8H2O

Picture of reaction:

Сoding to search: 2 HAuCl4 + 11 KOH + 3 HCHO = 2 Au + 3 HCOOK + 8 KCl + 8 H2O

Add / Edited: 24.01.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2H[AuCl₄] + 11KOH + 3HCHO → 2Au + 3HCOOK + 8KCl + 8H₂O

Add / Edited: 24.01.2015 /