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Gold(III) oxide react with hydrogen iodide

Au2O3 + 6HI → 2AuI + 2I2 + 3H2O




Gold(III) oxide react with hydrogen iodide to produce gold(I) iodide, iodine and water. Hydrogen iodide - concentrated cold solution.


Picture of reaction: img1 BB html

Сoding to search: Au2O3 + 6 HI = 2 AuI + 2 I2 + 3 H2O

Add / Edited: 24.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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