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Gold(I) sulfide react with chlorine and hydrogen chloride

Au2S + 3Cl2 + 2HCl → 2H[AuCl4] + S




Gold(I) sulfide react with chlorine and hydrogen chloride to produce hydrogen tetrachloridoaurate(III) and sulfur. Hydrogen chloride - concentrated solution.


Picture of reaction: img1 BB html

Сoding to search: Au2S + 3 Cl2 + 2 HCl = 2 HAuCl4 + S

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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