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Boron react with sodium hydroxide and oxygen

4B + 4NaOH + 3O2 → 4NaBO2 + 2H2O




Boron react with sodium hydroxide and oxygen to produce sodium metaborate and water. This reaction takes place at a temperature of 350-400°C.


Picture of reaction: img1 BB html

Сoding to search: 4 B + 4 NaOH + 3 O2 cnd [ temp ] = 4 NaBO2 + 2 H2O

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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