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Boron react with sulfur

2B + 3S → B2S3




Boron react with sulfur to produce boron(III) sulfide. This reaction takes place at a temperature of over 600°C.


Picture of reaction: img1 BB html

Сoding to search: 2 B + 3 S cnd [ temp ] = B2S3

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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