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Boron react with carbon disulfide

4B + 3CS2 → 2B2S3 + 3C




Boron react with carbon disulfide to produce boron(III) sulfide and carbon (graphite). This reaction takes place at a temperature near 930°C.


Picture of reaction: img1 BB html

Сoding to search: 4 B + 3 CS2 cnd [ temp ] = 2 B2S3 + 3 C

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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