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Boron carbide react with sodium hydroxide and water

B4C + 4NaOH + 12H2O → 4Na[B(OH)4] + 6H2 + C




Boron carbide react with sodium hydroxide and water to produce sodium tetrahydroxoborate(III), hydrogen and carbon (graphite). Sodium hydroxide - concentrated solution.


Picture of reaction: img1 BB html

Сoding to search: B4C + 4 NaOH + 12 H2O = 4 NaBOH4 + 6 H2 + C

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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