B4C + NaOH + H2O = Na[B(OH)4] + H2 + C |

B₄C + 4NaOH + 12H₂O → 4Na[B(OH)₄] + 6H₂ + C

Boron carbide react with sodium hydroxide and water to produce sodium tetrahydroxoborate(III), hydrogen and carbon (graphite). Sodium hydroxide - concentrated solution.

Find another reaction

Thermodynamic properties of substances

The solubility of the substances

Periodic table of elements

Boron carbide react with sodium hydroxide and water

B₄C + 4NaOH + 12H₂O → 4Na[B(OH)₄] + 6H₂ + C

Picture of reaction:

Сoding to search: B4C + 4 NaOH + 12 H2O = 4 NaBOH4 + 6 H2 + C

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Boron carbide react with sodium hydroxide and water

B4C + 4NaOH + 12H2O → 4Na[B(OH)4] + 6H2 + C

Picture of reaction:

Сoding to search: B4C + 4 NaOH + 12 H2O = 4 NaBOH4 + 6 H2 + C

Add / Edited: 25.01.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

B₄C + 4NaOH + 12H₂O → 4Na[B(OH)₄] + 6H₂ + C

Add / Edited: 25.01.2015 /