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Boron(III) chloride react with ammonia

BCl3 + 4NH3 → BN + 3NH4Cl

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Boron(III) chloride react with ammonia to produce boron(III) nitride and ammonium chloride. This reaction takes place at a temperature of 500-1000°C, in a flow H2.

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Picture of reaction: img1 BB html

Сoding to search: BCl3 + 4 NH3 cnd [ temp ] = BN + 3 NH4Cl

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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