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Boron(III) chloride react with aluminum phosphide

BCl3 + AlP → BP + AlCl3

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Boron(III) chloride react with aluminum phosphide to produce boron(III) phosphide and aluminum chloride. This reaction takes place at a temperature near 950°C.

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Сoding to search: BCl3 + AlP cnd [ temp ] = BP + AlCl3

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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