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Boron(III) chloride react with sulfur trioxide

2BCl3 + 3SO3 → B2O3 + 3SO2Cl2




Boron(III) chloride react with sulfur trioxide to produce boron trioxide(III) and sulfuryl chloride. This reaction takes place at a temperature near 120°C.


Picture of reaction: img1 BB html

Сoding to search: 2 BCl3 + 3 SO3 cnd [ temp ] = B2O3 + 3 SO2Cl2

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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