BCl3 + Li[BH4] = B2H6 + LiCl |

2BCl₃ + 6Li[BH₄] → 4B₂H₆ + 6LiCl

Boron(III) chloride react with tetrahydroxoborate(III) lithium to produce diborane and lithium chloride. This reaction takes place in the medium of ester.

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Boron(III) chloride react with tetrahydroxoborate(III) lithium

2BCl₃ + 6Li[BH₄] → 4B₂H₆ + 6LiCl

Picture of reaction:

Сoding to search: 2 BCl3 + 6 LiBH4 = 4 B2H6 + 6 LiCl

Add / Edited: 25.01.2015 /

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Boron(III) chloride react with tetrahydroxoborate(III) lithium

2BCl3 + 6Li[BH4] → 4B2H6 + 6LiCl

Picture of reaction:

Сoding to search: 2 BCl3 + 6 LiBH4 = 4 B2H6 + 6 LiCl

Add / Edited: 25.01.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2BCl₃ + 6Li[BH₄] → 4B₂H₆ + 6LiCl

Add / Edited: 25.01.2015 /