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Boron(III) fluoride react with water

BF3 + 2H2O → (H3O)[B(OH)F3]




Boron(III) fluoride react with water to produce hydronium hydroxotrifluoroborate(III). This reaction takes place at a temperature of no more 6°C.


Picture of reaction: img1 BB html

Сoding to search: BF3 + 2 H2O = H3OBOHF3

Add / Edited: 26.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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