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Boron(III) fluoride react with aluminum bromide

BF3 + AlBr3 → BBr3 + AlF3




Boron(III) fluoride react with aluminum bromide to produce boron(III) bromide and aluminum fluoride. This reaction takes place at a temperature near 100°C.


Picture of reaction: img1 BB html

Сoding to search: BF3 + AlBr3 cnd [ temp ] = BBr3 + AlF3

Add / Edited: 26.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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