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Boron(III), fluoride react with water and silicon dioxide

4BF3 + 6H2O + 3SiO2 → 4H3BO3 + 3SiF4

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Boron(III), fluoride react with water and silicon dioxide to produce orthoboric acid and silicon tetrafluoride. This reaction takes place slowly.

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Сoding to search: 4 BF3 + 6 H2O + 3 SiO2 = 4 H3BO3 + 3 SiF4

Add / Edited: 26.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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