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Boron(III) fluoride react with lithium hydride

8BF3 + 6LiH → B2H6 + 6Li[BF4]




Boron(III) fluoride react with lithium hydride to produce diborane and lithium tetrafluoroborate(III). This reaction takes place at a temperature near 35°C, in the medium of ester.


Picture of reaction: img1 BB html

Сoding to search: 8 BF3 + 6 LiH cnd [ temp ] = B2H6 + 6 LiBF4

Add / Edited: 26.01.2015 /

Evaluation of information: 3.0 out of 5 / number of votes: 2


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