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Boron(III) fluoride react with chlorine(III) fluoride

BF3 + ClF3 → [ClF2][BF4]




Boron(III) fluoride react with chlorine(III) fluoride to produce tetrafluoroborate(III) difluorochlorine(III). This reaction takes place at a temperature of no more 0°C.


Picture of reaction: img1 BB html

Сoding to search: BF3 + ClF3 = ClF2BF4

Add / Edited: 26.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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