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Sodium tetrafluoroborate(III) react with water

Na[BF4] + 3H2O → H3BO3 + NaF + 3HF




Sodium tetrafluoroborate(III) react with water to produce boric acid, sodium fluoride and hydrogen fluoride. The reaction takes place in a boiling solution.


Picture of reaction: img1 BB html

Сoding to search: NaBF4 + 3 H2O = H3BO3 + NaF + 3 HF

Add / Edited: 31.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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