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Sodium tetrafluoroborate(III) react with boron trioxide(III) and sulfuric acid

6Na[BF4] + B2O3 + 6H2SO4 → 8BF3 + 6NaHSO4 + 3H2O




Sodium tetrafluoroborate(III) react with boron trioxide(III) and sulfuric acid to produce boron trifluoride(III), sodium bisulfate and water. Sulfuric acid - concentrated solution.


Picture of reaction: img1 BB html

Сoding to search: 6 NaBF4 + B2O3 + 6 H2SO4 = 8 BF3 + 6 NaHSO4 + 3 H2O

Add / Edited: 31.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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