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Lithium tetrahydroxoborate(III) react with iodine

3Li[BH4] + 8I2 → 3LiI + 3BI3 + 4H2 + 4HI




Lithium tetrahydroxoborate(III) react with iodine to produce lithium iodide, boron(III) iodide, hydrogen and hydrogen iodide. The reaction takes place in a boiling solution in the hexane.


Picture of reaction: img1 BB html

Сoding to search: 3 LiBH4 + 8 I2 = 3 LiI + 3 BI3 + 4 H2 + 4 HI

Add / Edited: 01.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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