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The thermal decomposition of borazine

B3N3H6 → 3BN + 3H2


The thermal decomposition of borazine to produce boron nitride and hydrogen. This reaction takes place at a temperature near 300°C, or initiated by the absorption of energy in the form of light.


Picture of reaction: img1 BB html

Сoding to search: B3N3H6 cnd [ temp hν ] = 3 BN + 3 H2

Add / Edited: 01.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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