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Sodium tetrahydroxoborate(III) react with oxygen

Na[BH4] + 2O2 → NaBO2 + 2H2O




Sodium tetrahydroxoborate(III) react with oxygen to produce sodium metaborate and water. This reaction takes place at a temperature of over 300°C.


Picture of reaction: img1 BB html

Сoding to search: NaBH4 + 2 O2 cnd [ temp ] = NaBO2 + 2 H2O

Add / Edited: 02.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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