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Boron(III) iodide react with water

BI3 + 3H2O → H3BO3 + 3HI




Boron(III) iodide react with water to produce orthoboric acid and hydrogen iodide.


Picture of reaction: img1 BB html

Сoding to search: BI3 + 3 H2O = H3BO3 + 3 HI

Add / Edited: 02.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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