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Boron(III) iodide react with nitric acid and water

2BI3 + 2HNO3 + 2H2O → 2H3BO3 + 3I2 + 2NO




Boron(III) iodide react with nitric acid and water to produce orthoboric acid, iodine and nitric oxide. Nitric acid - diluted solution. The reaction takes place in a boiling solution.


Picture of reaction: img1 BB html

Сoding to search: 2 BI3 + 2 HNO3 + 2 H2O = 2 H3BO3 + 3 I2 + 2 NO

Add / Edited: 02.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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