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Boron(III) iodide react with nitric acid and water
2BI
3
+ 2HNO
3
+ 2H
2
O → 2H
3
BO
3
+ 3I
2
+ 2NO
[ Check the balance ]
Boron(III) iodide react with nitric acid and water to produce orthoboric acid, iodine and nitric oxide. Nitric acid - diluted solution. The reaction takes place in a boiling solution.
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Picture of reaction:
Сoding to search:
2 BI3 + 2 HNO3 + 2 H2O = 2 H3BO3 + 3 I2 + 2 NO
Add / Edited:
02.02.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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