Home Reactions Blog
Language: ru es en
Chemiday Log in:

Boron(III) iodide react with oxygen

2BI3 + 9O2 → B2O3 + 3I2O5

[ Check the balance ]
Boron(III) iodide react with oxygen to produce boron trioxide(III) and oxide iodine(V). This reaction takes place at a temperature of 150-175°C.

poiskFind another reaction
Thermodynamic properties Thermodynamic properties of substances
Table of solubility The solubility of the substances
Periodic Table Periodic table of elements

Picture of reaction: img1 BB html

Сoding to search: 2 BI3 + 9 O2 cnd [ temp ] = B2O3 + 3 I2O5

Add / Edited: 02.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | Author
Хостинг от uWebChemiDay.com © 2024
Cookies policy, User agreement, Privacy policy.