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Boron trioxide react with sodium hydroxide

B2O3 + 2NaOH → 2NaBO2 + H2O




Boron trioxide react with sodium hydroxide to produce sodium metaborate and water. This reaction takes place at a temperature of 400-550°C.


Picture of reaction: img1 BB html

Сoding to search: B2O3 + 2 NaOH cnd [ temp ] = 2 NaBO2 + H2O

Add / Edited: 03.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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