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Boron trioxide react with magnesium

B2O3 + 6Mg → Mg3B2 + 3MgO




Boron trioxide react with magnesium to produce magnesium boride and magnesium oxide. This reaction takes place at a temperature of 750-900°C.


Picture of reaction: img1 BB html

Сoding to search: B2O3 + 6 Mg cnd [ temp ] = Mg3B2 + 3 MgO

Add / Edited: 03.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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