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The thermal decomposition of sodium tetrahydroxoborate(III)

Na[B(OH)4] → NaBO2 + 2H2O




The thermal decomposition of sodium tetrahydroxoborate(III) to produce sodium metaborate and water. This reaction takes place at a temperature of over 306°C.


Picture of reaction: img1 BB html

Сoding to search: NaBOH4 cnd [ temp ] = NaBO2 + 2 H2O

Add / Edited: 03.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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