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Boron phosphide react with sulfur

4BP + 16S → 2B2S3 + P4S10




Boron phosphide react with sulfur to produce boron sulfide and phosphorus(V) sulfide. This reaction takes place at a temperature of 250-325°C.


Picture of reaction: img1 BB html

Сoding to search: 4 BP + 16 S cnd [ temp ] = 2 B2S3 + P4S10

Add / Edited: 04.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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