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Boron sulfide react with oxygen

2B2S3 + 9O2 → 2B2O3 + 6SO2




Boron sulfide react with oxygen to produce boron trioxide and sulfur dioxide. This reaction takes place at a temperature near 600°C.


Picture of reaction: img1 BB html

Сoding to search: 2 B2S3 + 9 O2 cnd [ temp ] = 2 B2O3 + 6 SO2

Add / Edited: 04.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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