(NH4)2[BeF4] = NH4F + BeF2 | The thermal decomposition of ammonium tetrafluoroberyllate(II)

(NH₄)₂[BeF₄] 2NH₄F + BeF₂

The thermal decomposition of ammonium tetrafluoroberyllate(II) to produce ammonium fluoride and beryllium fluoride. The reaction takes place at a temperature of 800-1100°C ^[8] (280°C^[16]).

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The thermal decomposition of ammonium tetrafluoroberyllate(II)

(NH₄)₂[BeF₄] 2NH₄F + BeF₂

Picture of reaction:

Сoding to search: NH42BeF4 cnd [ temp ] = 2 NH4F + BeF2

Add / Edited: 14.02.2015 /

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The thermal decomposition of ammonium tetrafluoroberyllate(II)

(NH4)2[BeF4] 2NH4F + BeF2

Picture of reaction:

Сoding to search: NH42BeF4 cnd [ temp ] = 2 NH4F + BeF2

Add / Edited: 14.02.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

(NH₄)₂[BeF₄] 2NH₄F + BeF₂

Add / Edited: 14.02.2015 /