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Bismuth(III) bromide react with sulfuric acid

4BiBr3 + 12H2SO4 → 2Bi2(SO4)3 + 6Br2 + 6SO2 + 12H2O




Bismuth(III) bromide react with sulfuric acid to produce bismuth(III) sulfate, bromine, sulfur dioxide and water. Sulfuric acid - concentrated solution.


Picture of reaction: img1 BB html

Сoding to search: 4 BiBr3 + 12 H2SO4 = 2 Bi2SO43 + 6 Br2 + 6 SO2 + 12 H2O

Add / Edited: 16.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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