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Bismuth(III) bromide react with bismuth(III) selenide

BiBr3 + Bi2Se3 → 3BiSeBr




Bismuth(III) bromide react with bismuth(III) selenide to produce bismuth(III) bromide-selenide. This reaction takes place at a temperature of 250-300°C.


Picture of reaction: img1 BB html

Сoding to search: BiBr3 + Bi2Se3 cnd [ temp ] = 3 BiSeBr

Add / Edited: 16.02.2015 /

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