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Bismuth(III) chloride react with sulfuric acid

2BiCl3 + 3H2SO4 → Bi2(SO4)3 + 6HCl




Bismuth(III) chloride react with sulfuric acid to produce bismuth(III) sulfate and hydrogen chloride. Sulfuric acid - concentrated solution. The reaction takes place in a boiling solution.


Picture of reaction: img1 BB html

Сoding to search: 2 BiCl3 + 3 H2SO4 = Bi2SO43 + 6 HCl

Add / Edited: 16.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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